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Proof step 6 from proof butlast-length (previous step)

# str = m + 1 ⊦ str = "", # l→s(s→l(str).butlast) = m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# str = m + 1 ⊦ str = "", # s→l(str).butlast = m

Rule argument

Additional information

Used simplifier rules: ⊦ # l→s(chars) = # chars;