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Proof step 1 from proof char-in-01 (conclusion)

⊦ char ∈ s→l(str) ↔ char ∈ str

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ char ∈ str ↔ char ∈ s→l(str)

Rule argument

spec: string-ops inst: name: in-def seq: ⊦ char ∈ str ↔ char ∈ s→l(str) subst: [str, char] → [str, char] flags: rewrite, current

Additional information

Used terms: str, char