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Proof step 12 from proof downcase-A (previous step)

28 ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[28 + (pos('a', sortedchars) - 28)] = 'a', pos('Z', sortedchars) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ pos('Z', sortedchars) = 53
Proof step 14:
28 ≤ 53 ⊦ s→l(sortedchars)[28 + (pos('a', sortedchars) - 28)] = 'a', 53 = 0

Rule argument

spec: string-less inst: name: pos-Z seq: ⊦ pos('Z', sortedchars) = 53 subst: flags: rewrite

Additional information

Used terms: