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Proof step 15 from proof downcase-A (previous step)

⊦ s→l(sortedchars)[28 + (pos('a', sortedchars) - 28)] = 'a'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ pos('a', sortedchars) = 58
Proof step 17:
⊦ s→l(sortedchars)[28 + (58 - 28)] = 'a'

Rule argument

spec: string-less inst: name: pos-a seq: ⊦ pos('a', sortedchars) = 58 subst: flags: rewrite

Additional information

Used terms: