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Proof step 19 from proof downcase-B (previous step)

58 = n0 + pos('A', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars), 29 ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ 29, pos('A', sortedchars) ≤ 58 ⊦ pos('Z', sortedchars) = 0, s→l(sortedchars)[29 + n0] = 'b'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ pos('A', sortedchars) = 28
Proof step 21:
58 = n0 + 28, 28 ≤ pos('Z', sortedchars), 29 ≤ pos('Z', sortedchars), 28 ≤ 29, 28 ≤ 58 ⊦ pos('Z', sortedchars) = 0, s→l(sortedchars)[29 + n0] = 'b'

Rule argument

spec: string-less inst: name: pos-A seq: ⊦ pos('A', sortedchars) = 28 subst: flags: rewrite

Additional information

Used terms: