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Proof step 3 from proof downcase-B (previous step)

¬(pos('A', sortedchars) ≤ pos('B', sortedchars) ∧ pos('B', sortedchars) ≤ pos('Z', sortedchars)) ⊦ downcase('B') = 'b'

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information