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Proof step 11 from proof downcase-C (previous step)

pos('A', sortedchars) ≤ pos('C', sortedchars) ∧ pos('C', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('C', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'c'

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
pos('A', sortedchars) ≤ pos('C', sortedchars), pos('C', sortedchars) ≤ pos('Z', sortedchars), pos('A', sortedchars) ≤ pos('Z', sortedchars) ⊦ s→l(sortedchars)[pos('C', sortedchars) + (pos('a', sortedchars) - pos('A', sortedchars))] = 'c'

Rule argument

Additional information

Used simplifier rules: ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1; (forward)