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Proof step 4 from proof last-app (previous step)

⊦ str1 = "", s→l(str0 + str1).last = str1.last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ str1 = "", (s→l(str0) + s→l(str1)).last = str1.last

Rule argument

Additional information

Used simplifier rules: ⊦ (str1 + str2) + str3 = str1 + str2 + str3;% ⊦ s→l(str + str0) = s→l(str) + s→l(str0);