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Proof step 6 from proof last-app (previous step)

⊦ s→l(str1) = [], str1 = "", (s→l(str0) + s→l(str1)).last = str1.last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ str1 = "", (s→l(str0) + s→l(str1)).last = str1.last

Rule argument

Additional information

Used simplifier rules: ⊦ s→l(str) = [] ↔ str = "";