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Proof step 8 from proof last-in (previous step)

s→l(str0).last ∈ str0 ⊦ char ' + str0 = "", (char ' + s→l(str0)).last = char, str0 = "", (char ' + s→l(str0)).last ∈ str0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ chars ≠ [] → (char ' + chars).last = chars.last

Rule argument

spec: list-last inst: charlist name: l-02 seq: ⊦ chars ≠ [] → (char ' + chars).last = chars.last subst: [chars, char] → [s→l(str0), char] flags: rewrite

Additional information

Used simplifier rules: ⊦ s→l(str) = [] ↔ str = ""; Used terms: s→l(str0), char