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Proof step 10 from proof natstring-chars (previous step)

char ∈ n→s(m), m < 10, ∀ m1, char. m1 < m → char ∈ n→s(m1) → char = '0' ∨ char = '9' ∨ char = '8' ∨ char = '7' ∨ char = '6' ∨ char = '5' ∨ char = '4' ∨ char = '3' ∨ char = '2' ∨ char = '1' ⊦ char = '1', char = '2', char = '3', char = '4', char = '5', char = '6', char = '7', char = '8', char = '9', char = '0'

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: string2nat inst: name: n2s-char seq: ⊦ n < 10 → n→s(n) = ( '0' + '1' + '2' + '3' + '4' + '5' + '6' + '7' + ('8' + '9') )[n ] + "" subst: [n] → [m] flags: rewrite

Additional information

Used terms: m