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Proof step 2 from proof natstring-chars (previous step)

char ∈ n→s(m) ⊦ char ∈ "0123456789"

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ char ∈ str ↔ char ∈ s→l(str)
Proof step 4:
char ∈ n→s(m) ⊦ char ∈ s→l("0123456789")

Rule argument

spec: string-ops inst: name: in-def seq: ⊦ char ∈ str ↔ char ∈ s→l(str) subst: [str, char] → ["0123456789", char] flags: rewrite, current

Additional information

Used terms: "0123456789", char