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Proof step 3 from proof prefix-num-01 (previous step)

str ⊑ str0 ⊦ str.char1 = str0.char1, str = "", str0 = ""

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
str = char + str1, str ⊑ str0 ⊦ char = str0.char1, str = "", str0 = ""

Rule argument

spec: string-data inst: name: elim seq: ⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0) subst: [str, char, str0] → [str, char0, str1] flags:

Additional information

Used simplifier rules: ⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0); (elim) Used terms: str, char0, str1