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Proof step 5 from proof prefix-num-01 (previous step)

char ' + str1 ⊑ str0 ⊦ str0 = "", char = str0.char1, char ' + str1 = ""

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: string-data inst: name: elim seq: ⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0) subst: [str, char, str0] → [str0, char1, str] flags:

Additional information

Used simplifier rules: ⊦ str ≠ "" → (char = str.char1 ∧ str0 = str.rstring ↔ str = char + str0); (elim) Used terms: str0, char1, str