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Proof step 2 from proof prefix-num (
previous step
)
str.char1 = str0.char1, str ≠ "", str0 ≠ "" ⊦ str ⊑ str0 ↔ str.rstring ⊑ str0.rstring
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
str.char1 = str0.char1 ⊦ str = "", str0 = "", str ⊑ str0 ↔ str.rstring ⊑ str0.rstring
Rule argument
Additional information