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Proof step 4 from proof prefix-num (previous step)

str = char + str1, char = str0.char1 ⊦ str = "", str0 = "", str ⊑ str0 ↔ str1 ⊑ str0.rstring

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ str0.char1 ' + str1 = "", str0 = "", str0.char1 ' + str1 ⊑ str0 ↔ str1 ⊑ str0.rstring

Rule argument

Additional information

Used simplifier rules: ⊦ char + str = char ' + str;