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Proof step 12 from proof right-trim-app (previous step)

str1.last ∈ str, char0 ∈ str1.butlast, ∀ char. char ∈ str1 → char ∈ str, ∀ str0, str, str2. # str2 < # str1 → (∀ char. char ∈ str2 → char ∈ str) → string-right-trim(str, str0 + str2) = string-right-trim(str, str0) ⊦ str1 = "", str0 + str1 = "", string-right-trim(str, str0 + str1.butlast) = string-right-trim(str, str0), char0 ∈ str

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: char0 abort: F discard: F computed: T

Additional information

Used simplifier rules: butlast-in: ⊦ ¬ char ∈ str ∧ str ≠ "" → ¬ char ∈ str.butlast; Used terms: char0