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Proof step 3 from proof right-trim-trim (previous step)

∀ str1, str. # str1 < # str0 → true → string-right-trim(str, string-right-trim(str, str1)) = string-right-trim(str, str1) ⊦ string-right-trim(str, string-right-trim(str, str0)) = string-right-trim(str, str0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ str2.last ∈ str1 ∧ str2 ≠ "" → string-right-trim(str1, str2) = string-right-trim(str1, str2.butlast)
Proof step 5:
str0.last ∈ str ∧ str0 ≠ "", ∀ str1, str. # str1 < # str0 → true → string-right-trim(str, string-right-trim(str, str1)) = string-right-trim(str, str1) ⊦ string-right-trim(str, string-right-trim(str, str0.butlast)) = string-right-trim(str, str0.butlast)

Rule argument

spec: string-ops inst: name: right-trim-rec seq: ⊦ str2.last ∈ str1 ∧ str2 ≠ "" → string-right-trim(str1, str2) = string-right-trim(str1, str2.butlast) subst: [str2, str1] → [str0, str] flags: rewrite, current

Additional information

Used simplifier rules: right-trim-empty: ⊦ string-right-trim(str1, "") = "";%right-trim-done: ⊦ ¬ str2.last ∈ str1 ∧ str2 ≠ "" → string-right-trim(str1, str2) = str2; Used terms: str0, str