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Proof step 6 from proof substring-offset-rec (previous step)

⊦ char ' + str0 = "", substring(char ' + str0, m0 + 1, n) = substring(str0, m0, n)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ substring(str, m, n) = l→s(sublist(m, n, s→l(str)))
Proof step 8:
⊦ char ' + str0 = "", l→s(sublist(m0 + 1, n, s→l(char ' + str0))) = substring(str0, m0, n)

Rule argument

spec: inst: name: substring-def seq: ⊦ substring(str, m, n) = l→s(sublist(m, n, s→l(str))) subst: [n, m, str] → [n, m0 + 1, char ' + str0] flags: rewrite, current

Additional information

Used terms: n, m0 + 1, char ' + str0