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Proof step 8 from proof substring-zero-rec (previous step)

⊦ char ' + str0 = "", l→s(sublist(0, m + 1, s→l(char ' + str0))) = char ' + substring(str0, 0, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ char ' + str0 = "", l→s(sublist(0, m + 1, char ' + s→l(str0))) = char ' + substring(str0, 0, m)

Rule argument

Additional information

Used simplifier rules: assoc: ⊦ (str1 + str2) + str3 = str1 + str2 + str3; from specification string-append%s2l-rec: ⊦ s→l(char ' + str) = char ' + s→l(str); from specification string2list