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Proof step 1 from proof upcase-a (conclusion)

⊦ upcase('a') = 'A'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ pos('a', sortedchars) ≤ pos(char, sortedchars) ∧ pos(char, sortedchars) ≤ pos('z', sortedchars) → upcase(char) = s→l(sortedchars)[pos(char, sortedchars) - (pos('a', sortedchars) - pos('A', sortedchars))]
Proof step 3:
¬(pos('a', sortedchars) ≤ pos('a', sortedchars) ∧ pos('a', sortedchars) ≤ pos('z', sortedchars)) ⊦ upcase('a') = 'A'
Proof step 8:
pos('a', sortedchars) ≤ pos('a', sortedchars) ∧ pos('a', sortedchars) ≤ pos('z', sortedchars) ⊦ s→l(sortedchars)[pos('a', sortedchars) - (pos('a', sortedchars) - pos('A', sortedchars))] = 'A'

Rule argument

spec: inst: name: Char-upcase-yes seq: ⊦ pos('a', sortedchars) ≤ pos(char, sortedchars) ∧ pos(char, sortedchars) ≤ pos('z', sortedchars) → upcase(char) = s→l(sortedchars) [ pos(char, sortedchars) - (pos('a', sortedchars) - pos('A', sortedchars)) ] subst: [char] → ['a'] flags: rewrite, current

Additional information

Used terms: 'a'