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Proof step 15 from proof upcase-a (previous step)

⊦ s→l(sortedchars)[58 - (58 - pos('A', sortedchars))] = 'A'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ pos('A', sortedchars) = 28
Proof step 17:
⊦ s→l(sortedchars)[58 - (58 - 28)] = 'A'

Rule argument

spec: string-less inst: name: pos-A seq: ⊦ pos('A', sortedchars) = 28 subst: flags: rewrite

Additional information

Used terms: