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Proof step 9 from proof upcase-a (previous step)

pos('a', sortedchars) ≤ pos('z', sortedchars) ⊦ s→l(sortedchars)[pos('a', sortedchars) - (pos('a', sortedchars) - pos('A', sortedchars))] = 'A'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ pos('a', sortedchars) = 58
Proof step 11:
58 ≤ pos('z', sortedchars) ⊦ s→l(sortedchars)[58 - (58 - pos('A', sortedchars))] = 'A'

Rule argument

spec: string-less inst: name: pos-a seq: ⊦ pos('a', sortedchars) = 58 subst: flags: rewrite

Additional information

Used terms: