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Proof step 4 from proof inject-s2l (previous step)

char ' + s→l(str1) = s→l(str0), char ∈ s→l(str0), ∀ str0. s→l(str1) = s→l(str0) → str1 = str0 ⊦ char ' + str1 = str0

User applied rule all left

And obtained the following new goals

Proof step 5:
char ' + s→l(str1) = s→l(str0), char ∈ s→l(str0), s→l(str1) = s→l(str0.rstring) → str1 = str0.rstring ⊦ char ' + str1 = str0

Rule argument

pos: left 3 terms: str0.rstring abort: F discard: T computed: F

Additional information

Used terms: str0.rstring