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Proof step 1 from proof pos-at (conclusion)

⊦ n < # str ∧ ¬ dups(s→l(str)) → pos(s→l(str)[n], str) = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n < # str ⊦ pos(s→l(str)[n], str) = n, str = "", dups(s→l(str))

Rule argument

Additional information

Used simplifier rules: ⊦ # str = 0 ↔ str = "";% ⊦ m < n → n ≠ 0; (forward)