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Proof step 1 from proof s2l-one (conclusion)

⊦ s→l(char ') = char '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
str ≠ "" ⊦ s→l((* str)) = str.char1 ' + s→l(str.rstring)

Rule argument

spec: string2list inst: name: s2l-rec-01 seq: str ≠ "" ⊦ s→l((* str)) = str.char1 ' + s→l(str.rstring) subst: [str] → [char '] flags: rewrite, current

Additional information

Used simplifier rules: s2l-empty: ⊦ s→l("") = [];% ⊦ char ' ≠ "";% ⊦ char '.char1 = char;% ⊦ char '.rstring = "";% ⊦ chars + [] = chars;% ⊦ (chars + chars0) + chars1 = chars + chars0 + chars1;% ⊦ char ' = char0 ' ↔ char = char0; Used terms: char '