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Proof step 28 from proof sortedchars-no-dups (previous step)

dups(s→l("!#$%&()*+-")) ∨ ( dups(s→l("./0123456789:<=>?@")) ∨ ( dups(s→l("ABCDEFGHIJKLM")) ∨ ( dups(s→l("NOPQRSTUVWXYZ")) ∨ ( dups(s→l("[]^_abcdefghi")) ∨ (dups(s→l("jklmnopqrs")) ∨ dups(s→l("tuvwxyz|~")) ∨ filter(s→l("jklmnopqrs"), s→l("tuvwxyz|~")) ≠ []) ∨ filter(s→l("[]^_abcdefghi"), s→l("jklmnopqrs") + s→l("tuvwxyz|~")) ≠ []) ∨ filter(s→l("NOPQRSTUVWXYZ"), s→l("[]^_abcdefghi") + s→l("jklmnopqrs") + s→l("tuvwxyz|~")) ≠ []) ∨ filter(s→l("ABCDEFGHIJKLM"), s→l("NOPQRSTUVWXYZ") + s→l("[]^_abcdefghi") + s→l("jklmnopqrs") + s→l("tuvwxyz|~")) ≠ []) ∨ filter(s→l("./0123456789:<=>?@"), s→l("ABCDEFGHIJKLM") + s→l("NOPQRSTUVWXYZ") + s→l("[]^_abcdefghi") + s→l("jklmnopqrs") + s→l("tuvwxyz|~")) ≠ []) ∨ filter (s→l("!#$%&()*+-"), s→l("./0123456789:<=>?@") + s→l("ABCDEFGHIJKLM") + s→l("NOPQRSTUVWXYZ") + s→l("[]^_abcdefghi") + s→l("jklmnopqrs") + s→l("tuvwxyz|~")) ≠ [] ⊦

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

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