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Proof step 67 from proof sortedchars-no-dups (previous step)

⊦ char ≠ 'i', char ≠ 'j' ∧ char ≠ 'k' ∧ char ≠ 'l' ∧ char ≠ 'm' ∧ char ≠ 'n' ∧ char ≠ 'o' ∧ char ≠ 'p' ∧ char ≠ 'q' ∧ char ≠ 'r' ∧ char ≠ 's' ∧ char ≠ 't' ∧ char ≠ 'u' ∧ char ≠ 'v' ∧ char ≠ 'w' ∧ char ≠ 'x' ∧ char ≠ 'y' ∧ char ≠ 'z' ∧ char ≠ '|' ∧ char ≠ '~'

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

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