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Proof step 10 from proof charn6 (previous step)

⊦ 4 = pos('6', '2' ' + '3' ' + '4' ' + '5' ' + '6' ' + '7' ' + '8' ' + '9' ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ char ≠ char0 → pos(char, char0 ' + chars) = pos(char, chars) + 1
Proof step 12:
'6' ≠ '2' ⊦ 4 = pos('6', '3' ' + '4' ' + '5' ' + '6' ' + '7' ' + '8' ' + '9' ') + 1

Rule argument

spec: list-del inst: charlist name: pos-n seq: ⊦ char ≠ char0 → pos(char, char0 ' + chars) = pos(char, chars) + 1 subst: [chars, char0, char] → ['3' ' + '4' ' + '5' ' + '6' ' + '7' ' + '8' ' + '9' ', '2', '6'] flags: rewrite

Additional information

Used terms: '3' ' + '4' ' + '5' ' + '6' ' + '7' ' + '8' ' + '9' ', '2', '6'