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Proof step 21 from proof charn8 (previous step)

'8' ≠ '5' ⊦ 3 = pos('8', '6' ' + '7' ' + '8' ' + '9' ') + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
⊦ 2 = pos('8', '6' ' + '7' ' + '8' ' + '9' ')

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;%n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0;