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Proof step 22 from proof inject-n2s (previous step)

m < 10, ('0' + '1' + '2' + '3' + '4' + '5' + '6' + '7' + ('8' + '9'))[m] + "" = n→s(n), ∀ m1, n. m1 < m → n→s(m1) = n→s(n) → m1 = n ⊦ m = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
('0' ' + '1' ' + '2' ' + '3' ' + '4' ' + '5' ' + '6' ' + '7' ' + '8' ' + '9' ')[m] ' = n→s(n), m < 10, ∀ m1, n. m1 < m → n→s(m1) = n→s(n) → m1 = n ⊦ m = n

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)% ⊦ (str1 + str2) + str3 = str1 + str2 + str3;% ⊦ str1 + "" = str1;% ⊦ char + str = char ' + str;% ⊦ char + chars = char ' + chars;% ⊦ char + char0 = char ' + char0 ';