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Proof step 52 from proof n2s-chars (previous step)

10 ≤ m, ∀ m1, char. m1 < m → true → ¬ char ∈ '0' + '1' + '2' + '3' + '4' + '5' + '6' + '7' + ('8' + '9') → ¬ char ∈ s→l(n→s(m1)) ⊦ char = '0', char = '9', char = '8', char = '7', char = '6', char = '5', char = '4', char = '3', char = '2', char = '1', m = 0, ¬ char ∈ s→l(n→s(m / 10)) ∧ ¬ char ∈ s→l(n→s(m % 10))

User applied rule apply induction

And obtained the following new goals

Rule argument

subst: [char, m1] → [char, m / 10]

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;%m0 ≠ 0 ⊦ n ≤ m / m0 ↔ n * m0 ≤ m;% ⊦ n ≠ 0 → (m * n ≤ n ↔ m ≤ 1);% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m; Used terms: char, m / 10