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Proof step 3 from proof n2s-empty (previous step)

n→s(n) = "", ∀ n0. n0 < n → n→s(n0) = "" → false ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
n→s(n) = "", ∀ n0. n0 < n → n→s(n0) = "" → false ⊦

Rule argument

Additional information