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Proof step 50 from proof n2s-zero (previous step)

'5' ' + '6' ' + '7' ' + '8' ' + '9' ' ≠ [] ∧ m ≠ 0, ('5' ' + '6' ' + '7' ' + '8' ' + '9' ').rest[m - 1] ' = "0", m < 5 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
('6' ' + '7' ' + '8' ' + '9' ')[m - 1] ' = "0", m < 5 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: e-01: ⊦ char ' + chars ≠ []; from specification list[charlist]%a: ⊦ (chars + chars0) + chars1 = chars + chars0 + chars1; from specification list[charlist]%c-07: ⊦ (char ' + chars).rest = chars; from specification list[charlist]