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Proof step 55 from proof n2s-zero (previous step)

¬('6' ' + '7' ' + '8' ' + '9' ' ≠ [] ∧ m0 ≠ 0), ('6' ' + '7' ' + '8' ' + '9' ')[m0] ' = "0", m0 < 4 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
'6' ' = "0" ⊦

Rule argument

Additional information

Used simplifier rules: get-zero-01: ⊦ (char ' + chars)[0] = char; from specification list-del[charlist]%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic1%a: ⊦ (chars + chars0) + chars1 = chars + chars0 + chars1; from specification list[charlist]%e-01: ⊦ char ' + chars ≠ []; from specification list[charlist]