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Proof step 74 from proof n2s-zero (previous step)

'8' ' + '9' ' ≠ [] ∧ m0 ≠ 0, ('8' ' + '9' ').rest[m0 - 1] ' = "0", m0 < 2 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 75:
'9' ' = "0" ⊦

Rule argument

Additional information

Used simplifier rules: one-03: ⊦ char '[0] = char; from specification list-del[charlist]%twols-02: ⊦ m ≠ 0 → (m < 2 ↔ m = 1); from specification nat-basic1%e-01: ⊦ char ' + chars ≠ []; from specification list[charlist]%a: ⊦ (chars + chars0) + chars1 = chars + chars0 + chars1; from specification list[charlist]%c-07: ⊦ (char ' + chars).rest = chars; from specification list[charlist]