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Proof step 9 from proof s2n-app (previous step)

∀ str0. str0 = "" ∨ s→n(str2 + str0) = s→n(str2) * 10 ^ # str0 + s→n(str0) ⊦ str0 = "", char0 ' + str2 = "", str2 = "", s→n(str2 + str0) = 10 ^ # str0 * s→n(str2) + s→n(str0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: str0

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult Used terms: str0