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Proof step 7 from proof eqd-implies-lbnif (conclusion)

eqd(sys, d, sys0) ⊦ ∀ nam. cdom(nam) ⇒ d → contents(sys, nam) = contents(sys0, nam)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
eqd(sys, d, sys0), cdom(nam) ⇒ d, eqd(sys0, d, sys) ⊦ contents(sys, nam) = contents(sys0, nam)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : MeydenIntrans, , eqd-reflexivity, ⊦ eqd(sys, d, sys)], [CSIMPNAMEDFORWARD : MeydenIntrans, , eqd-transitivity, ⊦ eqd(sys, d, sys0) ∧ eqd(sys0, d, sys1) → eqd(sys, d, sys1)], [CSIMPNAMEDFORWARD : MeydenIntrans, , eqd-symmetry, ⊦ eqd(sys, d, sys0) → eqd(sys0, d, sys)])]]