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Proof step 1 from proof BSD-unwind-theorem (previous step)

⊦ BSP_BSD ↔ (∀ tr, tr0, ev. view(ev) = C ∧ (tr0 + (ev + tr)) ∈TR ∧ proj(tr, Cview(view)) = [] → (∃ tr1. (tr0 + tr1) ∈TR ∧ proj(tr1, Vview(view)) = proj(tr, Vview(view)) ∧ proj(tr1, Cview(view)) = []))

Lemma BSP_BSD-def