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Proof step 12 from proof eqd-transitivity (conclusion)

⊦ eqd(sys, d, sys0) ∧ eqd(sys0, d, sys1) → eqd(sys, d, sys1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : eqd-symmetry, , , ⊦ eqd(sys, d, sys0) → eqd(sys0, d, sys)])]]