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Proof step 7 from proof sources-in-one (conclusion)
⊦ d0 ∈ sources(co ', d) ↔ d0 = d ∨ d0 = cdom(co) ∧ d0 ⇒ d
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
⊦ d0 ∈ sources(co ', d) ↔ d0 = d ∨ d0 = cdom(co) ∧ cdom(co) ⇒ d
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]