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Proof step 58 from proof sources-in-two (previous step)

⊦ d0 ∈ sources(co ' + co0 ', d) ↔ d0 = d ∨ d0 = cdom(co0) ∧ cdom(co0) ⇒ d ∨ d0 = cdom(co) ∧ cdom(co) ⇒ d ∨ d0 = cdom(co) ∧ cdom(co) ⇒ cdom(co0) ∧ cdom(co0) ⇒ d

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ sources(co ' + cl, d) = (((∃ d0. d0 ∈ sources(cl, d) ∧ cdom(co) ⇒ d0) ⊃ sources(cl, d) ++ cdom(co); sources(cl, d)))

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: sources-rec antecedent: succedent: sources(co ' + cl, d) = (((∃ d0. d0 ∈ sources(cl, d) ∧ cdom(co) ⇒ d0) ⊃ sources(cl, d) ++ cdom(co) ; sources(cl, d) ) ) substlist: [d, cl, co] → [d, co0 ', co] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0, 1, 0, 1, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (d, co0 ', co)]]