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Proof step 8 from proof sources-interfere (previous step)

cdom(co) ⇒ d, ∀ co, d. co ∈ cl0 ∧ cdom(co) ⇒ d → cdom(co) ∈ sources(cl0, d) ⊦ cdom(co) ∈ sources(co0 ' + cl0, d), co ≠ co0 ∧ ¬ co ∈ cl0

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 7:
cdom(co) ⇒ d, co ∈ cl0 ∧ cdom(co) ⇒ d → cdom(co) ∈ sources(cl0, d), ∀ co, d. co ∈ cl0 ∧ cdom(co) ⇒ d → cdom(co) ∈ sources(cl0, d) ⊦ cdom(co) ∈ sources(co0 ' + cl0, d), co ≠ co0 ∧ ¬ co ∈ cl0

Rule argument

[EXRARG : pos: left 2, [QUANTTERMLIST : (co, d)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (co, d)]]