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Proof step 1 from proof sources-one-transitive (
previous step
)
⊦ sources(co ', d) = (((∃ d0. d0 ∈ sources([], d) ∧ cdom(co) ⇒ d0) ⊃ sources([], d) ++ cdom(co); sources([], d)))
Lemma
sources-one