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Proof step 6 from proof lemma5-2 (previous step)

eqS(sys, sys0), eqds(sys, sources([], d), sys0) ⊦ eqd(run(sys, []), d, run(sys0, ipurge([], d)))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : sources-base, , , ⊦ sources([], d) = ∅ ++ d], [CSIMPNAMEDSEQ : run-base, , , ⊦ run(sys, []) = sys], [CSIMPNAMEDSEQ : ipurge-base, , , ⊦ ipurge([], d) = []])]]