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Proof step 1 from proof sources-rec-lem (
previous step
)
⊦ sources(sys, co + cl, d) = (((∃ d0. d0 ∈ sources(exec(sys, co) .1, cl, d) ∧ cdom(sys, co) ⇒ d0) ⊃ sources(exec(sys, co) .1, cl, d) ++ cdom(sys, co) ; sources(exec(sys, co) .1, cl, d) ) )
Lemma
sources-rec