[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 11 from proof transex-enabled-intrans (
previous step
)
trans∃(trans, S0, tr, s0), enabled(trans, s0, tr1) ⊦ tr + tr1 ∈TR trans
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 1
:
⊦ tr ∈TR trans ↔ enabled(trans, S0, tr)
Rule argument
[x0lemmaarg: spec-name: instance-name: lemma-name: in-trace-def antecedent: succedent: tr ∈TR trans ↔ enabled(trans, S0, tr) substlist: [trans, tr] → [trans, tr + tr1] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0)) dummy: () ]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (trans, tr + tr1)]]