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Proof step 3 from proof transex-one (conclusion)

⊦ trans∃(trans, s1, ev ', s2) ↔ trans(s1, ev, s2)

User applied rule insert lemma

And obtained the following new goals

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: transex-rec antecedent: succedent: trans∃(trans, s, ev ' + tr, s0) ↔ (∃ s1. trans(s, ev, s1) ∧ trans∃(trans, s1, tr, s0)) substlist: [trans, s, ev, tr, s0] → [trans, s1, ev, [], s2] add preconditions?: F is rewrite lemma?: F current spec?: T rotate lemma?: F replace all?: F paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : transex-empty, , , ⊦ trans∃(trans, s, [], s0) ↔ s = s0], [CSIMPSEQ : ⊦ tr + [] = tr], [CSIMPSEQ : ⊦ (tr + tr0) + tr1 = tr + tr0 + tr1])], [EXTRATERMS : (trans, s1, ev, [], s2)]]