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Proof step 11 from proof eqd-transitivity (conclusion)

⊦ eqd(sys, d, sys0) ∧ eqd(sys0, d, sys1) → eqd(sys, d, sys1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
eqd(sys0, d, sys1), eqd(sys, d, sys0) ⊦ eqd(sys, d, sys1)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]