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Proof step 4 from proof isEqRel-symmetric (previous step)

eqstate(s0, s), isEqRel(eqstate) ⊦ eqstate(s, s0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ isEqRel(eqstate) ↔ (∀ s. eqstate(s, s)) ∧ (∀ s, s0. eqstate(s, s0) → eqstate(s0, s)) ∧ (∀ s, s0, s1. eqstate(s, s0) ∧ eqstate(s0, s1) → eqstate(s, s1))

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: isEqRel-def antecedent: succedent: isEqRel(eqstate) ↔ (∀ s. eqstate(s, s)) ∧ (∀ s, s0. eqstate(s, s0) → eqstate(s0, s)) ∧ (∀ s, s0, s1. eqstate(s, s0) ∧ eqstate(s0, s1) → eqstate(s, s1)) substlist: [eqstate] → [eqstate] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((0, 0, 1)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (eqstate)]]